Solving Systems by Substitution
-x - 6y=15
y = 6x +16
We can solve this system of equations by substituting the second equation into the first equation.
First, plug in the value of y from the second equation into the first equation:
-x - 6(6x +16) = 15
Simplify the equation by distributing the -6:
-x - 36x - 96 = 15
Combine like terms:
-37x - 96 = 15
Add 96 to both sides:
-37x = 111
Divide by -37 on both sides to solve for x:
x = -3
Now that we have found the value of x, we can substitute it back into the second equation to find the value of y:
y = 6(-3) + 16
y = -18 + 16
y = -2
Therefore, the solution to the system of equations is x = -3 and y = -2.
-6 .*23
The product of -6 and 23 is:
-6 * 23 = -138
16 +138
The sum of 16 and 138 is:
16 + 138 = 154
-21 + 23
The sum of -21 and 23 is:
-21 + 23 = 2
-21 - 22
The difference between -21 and 22 is:
-21 - 22 = -43