The function g is defined as follows for the domain given.
g(x) = 1 - 2x domain = {-1, 0, 1, 2}
Write the range of g using set notation. Then graph g
The range of g using set notation is {1, -1, -3, -5}
Graph of g:
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-5 *---|--------------*
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-6 *---|--------------*
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-7
what is the graph
I apologize for the confusion in my previous response. Here is the corrected graph of the function g(x) = 1 - 2x for the given domain { -1, 0, 1, 2 }:
For x = -1:
g(-1) = 1 - 2(-1) = 1 + 2 = 3
For x = 0:
g(0) = 1 - 2(0) = 1
For x = 1:
g(1) = 1 - 2(1) = 1 - 2 = -1
For x = 2:
g(2) = 1 - 2(2) = 1 - 4 = -3
Therefore, the graph of g with the given domain will have the points (-1, 3), (0, 1), (1, -1), and (2, -3). Connecting these points will give the graph of g as follows:
4 *
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3 *
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2 *--------------*
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1 *
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0 *--------------*
-1 0 1 2
I hope this clarifies things for you. Thank you for your understanding.
what is the answer in y-intercept form
The y-intercept form of a linear function is y = mx + b, where m is the slope and b is the y-intercept.
In the case of the function g(x) = 1 - 2x, the y-intercept occurs when x = 0. Substituting x = 0 into the function, we get:
g(0) = 1 - 2(0) = 1
Therefore, the y-intercept of the function g is at the point (0, 1).
So, g(x) can be written in y-intercept form as y = -2x + 1.