an object can accelerate at 9.85 m/s2 [forward] starting from rest how long will it take the object to travel a displacement of 422m [forward]
To find the time it takes for the object to travel a displacement of 422m, we can use the kinematic equation:
s = (1/2)at^2
Where:
s = displacement = 422m
a = acceleration = 9.85 m/s^2
t = time
First, rearrange the equation to solve for time:
2s = at^2
t^2 = 2s / a
t = sqrt(2s / a)
Plugging in the values:
t = sqrt(2 * 422m / 9.85 m/s^2)
t = sqrt(844 / 9.85)
t = sqrt(85.532)
t = 9.25 seconds
Therefore, it will take the object 9.25 seconds to travel a displacement of 422m with an acceleration of 9.85 m/s^2.