Hydrogen sulfide, H,S, has the characteristic odor of rotten eggs. If a sample of H, gas at 729.6 torr and 25.1 °C in a 45.6 mL, container is allowed to enter a 69.9 mL container at a pressure of 896.0 torr, what is the temperature in the new container? Be sure your answer has the correct number of significant figures.

Question

Hydrogen sulfide, H,S, has the characteristic odor of rotten eggs. If a sample of H, gas at 729.6 torr and 25.1 °C in a 45.6 mL, container is allowed to enter a 69.9 mL container at a pressure of 896.0 torr, what is the temperature in the new container? Be sure your answer has the correct number of significant figures.

Answer 1

First, we need to use the ideal gas law to find the moles of hydrogen sulfide in the initial container:

PV = nRT

(729.6 torr)(0.0456 L) = n(0.08206 L.atm/mol.K)(298.1 K)
33.266 torr.L = 24.37n
n = 1.36 mol

Next, we need to find the new temperature in the larger container using the ideal gas law and the moles of hydrogen sulfide we calculated:

PV = nRT

(896.0 torr)(0.0699 L) = (1.36 mol)(0.08206 L.atm/mol.K)(T)
62.49 = 0.1114T
T = 561.2 K

Therefore, the temperature in the new container is 561.2 K.