A chemical equation for the reaction between calcium hydroxide, Ca(OH)2 , and sulfuric acid, H2SO4, is shown. The masses of some of the reactants and products are given in grams.
Ca(OH)2 + H2SO4 → CaSO4 + 2H2O
74 g ? 136 g 36 g
How many grams of sulfuric acid were used in the reaction?
1.62 g
2.36 g
3.100 g
4.98 g
2. 36 g
To solve this problem, we can use the stoichiometry of the reaction. From the balanced equation, we can see that 1 mole of calcium hydroxide reacts with 1 mole of sulfuric acid.
First, we need to determine the number of moles of calcium hydroxide used in the reaction:
74 g Ca(OH)2 * (1 mol Ca(OH)2 / 74 g Ca(OH)2) = 1 mol Ca(OH)2
From the stoichiometry of the reaction, we know that 1 mol Ca(OH)2 reacts with 1 mol H2SO4.
Now, we can use this information to determine the amount of sulfuric acid used in grams:
(1 mol H2SO4 / 1 mol Ca(OH)2) * (98 g H2SO4 / 1 mol H2SO4) = 36 g H2SO4
Therefore, 36 grams of sulfuric acid were used in the reaction.