The mean temperature during the summer in a certain city is 80 degrees Fahrenheit, with a standard deviation of 5 degrees Fahrenheit. What is the probability that a randomly selected day has a temperature below 73 degrees Fahrenheit?
A. 91.92%
B. 4.75%
C. 8.08%
D. 95.25
To solve this problem, we can use the Z-score formula:
Z = (X - μ) / σ
Where:
Z = Z-score
X = Value we are interested in (73 degrees Fahrenheit)
μ = Mean temperature (80 degrees Fahrenheit)
σ = Standard deviation (5 degrees Fahrenheit)
Plugging in the values:
Z = (73 - 80) / 5
Z = -1.4
Next, we can find the probability of a temperature below 73 degrees Fahrenheit by looking up the Z-score in a standard normal distribution table.
We find that the probability associated with a Z-score of -1.4 is approximately 0.0808 or 8.08%.
Therefore, the answer is:
C. 8.08%
is this right
I apologize for the mistake in my previous response. Let's correct the calculation:
To find the probability that a randomly selected day has a temperature below 73 degrees Fahrenheit, we need to calculate the Z-score for 73 degrees Fahrenheit using the formula:
Z = (X - μ) / σ
Z = (73 - 80) / 5
Z = -1.4
Next, we will look up the Z-score of -1.4 in a standard normal distribution table. The probability corresponding to a Z-score of -1.4 is approximately 0.0808 or 8.08%.
Therefore, the correct answer is:
C. 8.08%