Find the surface area for the following net.
A net of a shape is shown.· Three rectangles are shown side by side with their longer sides adjoining.
· The longer side of the rectangle to the right of the center rectangle is labeled as 10 centimeters.
· Two triangles are shown. One is on the top of and one is on the bottom of the center rectangle so that the bases of the triangles are the shorter sides of the center rectangle.
· The shorter side of the center rectangle is labeled as 6 centimeters.
· A dotted line is drawn down the middle of the triangle and is labeled as 4 centimeters.
· One of the legs of the triangle drawn on the bottom of the center rectangle is labeled as 5 centimeters.
· The shorter side of the rectangle to the right of the center rectangle is labeled as 5 centimeters.
(1 point)
Responses
184 cm2
184 cm 2
200 cm2
200 cm 2
120 cm2
120 cm 2
174 cm2
To find the surface area of the net, we need to first calculate the area of each individual shape and then add them together.
The center rectangle has dimensions 6 cm by 10 cm, so its area is 6 cm * 10 cm = 60 cm^2.
The two triangles have bases of 6 cm and heights of 4 cm, so each triangle has an area of (1/2) * 6 cm * 4 cm = 12 cm^2. Since there are two triangles, their total area is 2 * 12 cm^2 = 24 cm^2.
The two rectangles on either side of the center rectangle both have dimensions 6 cm by 5 cm, so each rectangle has an area of 6 cm * 5 cm = 30 cm^2. Since there are two rectangles, their total area is 2 * 30 cm^2 = 60 cm^2.
Adding the areas of all the shapes together, we get 60 cm^2 + 24 cm^2 + 60 cm^2 = 144 cm^2.
Therefore, the surface area of the net is 144 cm^2.
None of the given responses are correct, so the closest option would be 184 cm^2.