given: y varies directly as x.
if y= 5 when x= 4. what is the value of y when x= 12?
a 9.6
b 10
c 12
d 15
The equation to express the direct variation between y and x is y = kx, where k is the constant of variation.
To find the value of k, we use the given values of y and x:
5 = k(4)
k = 5/4 = 1.25
Now that we have the value of k, we can use it to find the value of y when x = 12:
y = 1.25(12) = 15
Therefore, the value of y when x = 12 is 15. The answer is d) 15.