Teshome bought 6 pencils and 2 rubber erasers from a shop and
paid a total of Birr 3. Meskerem also paid a total of Birr 3 for 4
pencils and 3 rubber erasers.
Let the cost of one pencil be x Birr and the cost of one rubber eraser be y Birr.
From the given information, we can create the following equations:
6x + 2y = 3 (Teshome's purchase)
4x + 3y = 3 (Meskerem's purchase)
To solve these equations, we can use the substitution method:
From the first equation:
2y = 3 - 6x
y = (3 - 6x) / 2
Substitute y into the second equation:
4x + 3(3 - 6x) / 2 = 3
4x + 9/2 - 9x = 6
-5x + 9/2 = 6
-5x = 3/2
x = -3/10
Now, substitute x back into the equation to solve for y:
6(-3/10) + 2y = 3
-18/10 + 2y = 3
2y = 48/10
y = 24/10
y = 2.4
Therefore, the cost of one pencil is 0.3 Birr and the cost of one rubber eraser is 2.4 Birr.