A 125 N object vibrates with a period of 3.56 s when hanging from a spring. What is
the spring constant of the spring?
To find the spring constant, we can use the formula for the period of a mass hanging from a spring:
T = 2π√(m/k)
Where:
T = period of vibration
m = mass of the object (125 N)
k = spring constant
Given that the period of vibration is 3.56 s and the mass of the object is 125 N, we can plug these values into the formula and solve for k:
3.56 = 2π√(125/k)
3.56/2π = √(125/k)
(3.56/2π)^2 = 125/k
12.37 = 125/k
k = 125/12.37
k ≈ 10.12 N/m
Therefore, the spring constant of the spring is approximately 10.12 N/m.