How much force is required to pull a spring 3.0 cm from its equilibrium position if
the spring constant is 2.7 × 103 N/m?
To calculate the force required to pull a spring 3.0 cm from its equilibrium position, we can use Hooke's Law:
F = kx
where F is the force applied, k is the spring constant (2.7 x 10^3 N/m), and x is the displacement from the equilibrium position (3.0 cm = 0.03 m).
Plugging in the values, we get:
F = (2.7 x 10^3 N/m)(0.03 m)
F = 81 N
Therefore, the force required to pull the spring 3.0 cm from its equilibrium position is 81 N.