The molar mass of ammonium acetate is 77.083 g/mol. A student uses 0.100 mol of ammonium acetate in a chemical reaction. The student claims that the reaction uses (0.100 mol)(77.083 g/mol)=7.71 g of ammonium acetate, which has
(7.71)(6.022×10^23)=4.64×10^24 molecules.
The student's calculation is correct.
0.100 mol of ammonium acetate is equivalent to (0.100 mol)(77.083 g/mol) = 7.7083 g of ammonium acetate.
To find the number of molecules in 7.71 g of ammonium acetate, we can use the conversion factor 1 mol = 6.022×10^23 molecules.
(7.71 g)(1 mol/77.083 g)(6.022×10^23 molecules/mol) = 4.64×10^24 molecules
Therefore, the student's claim is correct and there are 4.64×10^24 molecules in 0.100 mol of ammonium acetate.