If a person exhales 31.5 g of CO2 in an hour, what volume (in L) does this amount occupy at 1.06 atm and 37.2 C? Be sure your answer has the correct
number of significant figures.
Note: Reference the Fundamental constants table for additional information.
To calculate the volume of CO2 gas at the given conditions, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (1.06 atm)
V = volume
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (37.2 C = 310.35 K)
First, we need to calculate the number of moles of CO2 present:
31.5 g CO2 * (1 mol CO2 / 44.01 g) = 0.716 mol CO2
Now, we can rearrange the ideal gas law equation to solve for V:
V = (nRT) / P
V = (0.716 mol * 0.0821 L.atm/mol.K * 310.35 K) / 1.06 atm
V = 18.91 L
Therefore, 31.5 g of CO2 at 1.06 atm and 37.2 C occupies 18.91 L. Be sure to round your answer to 3 significant figures.