If it takes 35.0 joules of heat to raise the temperature of 17.0 g of a substance 9.50 °C, what is the specific heat of the substance? Be sure your answer has the
correct number of significant figures.
Specific heat =
J
g.℃
Specific heat = q / (m * ΔT)
Specific heat = 35.0 J / (17.0 g * 9.50 °C)
Specific heat = 0.2061559633 J/(g·°C)
Therefore, the specific heat of the substance is 0.206 J/(g·°C).