25x^2+60x+36
This is a quadratic equation in the form of \(ax^2 + bx + c\). In this case, \(a = 25\), \(b = 60\), and \(c = 36\).
To solve for x, we can use the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Plugging in the values of \(a\), \(b\), and \(c\):
\[ x = \frac{-60 \pm \sqrt{60^2 - 4(25)(36)}}{2(25)} \]
\[ x = \frac{-60 \pm \sqrt{3600 - 3600}}{50} \]
\[ x = \frac{-60 \pm \sqrt{0}}{50} \]
Since the square root of 0 is 0, there is only one solution:
\[ x = \frac{-60}{50} \]
\[ x = -\frac{6}{5} \]
Therefore, the solution to the equation is \(x = -\frac{6}{5}\).