Consider the following data:
19 10 9 8 14 11 11 12 11 9 19 19
17 10 13 18 16 17 5 14 11 15 18 12
8 7 10 16 2 12
Construct a frequency distribution by making the class width 3 and the lower limit of the first class 2.
Intervals / Intervalle Class Midpoints / Klasmiddelpunte Frequencies / Frekwensies Cumulative frequency / Kumulatiewe frekwensies Relative frequency / Relatiewe frekwensie
[ - )
[ A - ) D H J
[ - ) F
[ - B ) K
[ - ) E I
[ - ) G
Total C
What is the value of D in the table?
3.5
6.5
12.5
18.5
In the given data, the class width is 3, so the midpoint of the class D would be the lower limit of class D + class width / 2.
Lower limit of class D = 11,
Class width = 3
Midpoint of class D = 11 + 3 / 2 = 11 + 1.5 = 12.5
Therefore, the value of D in the table is 12.5.