Aleksandr has a roll of paper that is in the shape of a right circular cylinder. It has a height of 28 cm and a diameter of 15.5 cm. Help Aleksandr solve for the surface area. Use 3.14 for π.(1 point)
Responses
1,739.95 cm2
1,739.95 cm squared
1,362.76 cm2
1,362.76 cm squared
4,234.29 cm2
4,234.29 cm squared
1,508.77 cm2
To find the surface area of a right circular cylinder, you need to find the area of the two circular bases and the lateral surface area.
1. Area of each circular base: A = πr^2, where r is the radius (half of the diameter)
r = 15.5 cm / 2 = 7.75 cm
A = 3.14 * (7.75)^2 = 3.14 * 60.0625 = 188.75 cm^2 (for each base)
2. Lateral surface area: A = 2πrh, where r is the radius and h is the height
A = 2(3.14)(7.75)(28) = 1739.95 cm^2
3. Total surface area = 2(188.75) + 1739.95 = 377.5 + 1739.95 = 2117.45 cm^2
So, the correct response is:
1,739.95 cm^2