Solve the system of equations.%0D%0A5x+2y=14 %0D%0Ax−6y=22
To solve this system of equations, we can use the substitution method.
First, we can solve the second equation for x:
x - 6y = 22
x = 6y + 22
Now, we can plug the expression for x into the first equation:
5(6y + 22) + 2y = 14
30y + 110 + 2y = 14
32y + 110 = 14
32y = -96
y = -3
Now that we have found the value for y, we can plug it back into the second equation to find the value of x:
x = 6(-3) + 22
x = -18 + 22
x = 4
Therefore, the solution to the system of equations is x = 4 and y = -3.