What is the surface area of the three-dimensional figure represented by this net?%0D%0A%0D%0A%0D%0A%0D%0A%0D%0AA. %0D%0A57 square inches%0D%0A%0D%0A%0D%0AB. %0D%0A60 square inches%0D%0A%0D%0A%0D%0AC. %0D%0A105 square inches%0D%0A%0D%0A%0D%0AD. %0D%0A108 square inches
To find the surface area of the three-dimensional figure represented by the net, we need to calculate the area of each face and then add them together.
Looking at the net, we see that there are 4 rectangles that make up the sides of the figure, each with dimensions 6 inches by 3 inches. The total area of these rectangles is 4 * (6 * 3) = 72 square inches.
Additionally, we have 2 squares at the top and bottom of the figure, each with dimensions 3 inches by 3 inches. The total area of these squares is 2 * (3 * 3) = 18 square inches.
Adding the area of the rectangles and squares together, we get 72 + 18 = 90 square inches.
Therefore, the correct answer is not listed. The actual surface area is 90 square inches.
A 57
B 60
C 105
D 108
Let's review the net representation. Since we have 4 rectangles with dimensions 6 inches by 3 inches, we can calculate the total area of these rectangles as 4 * (6 * 3) = 72 square inches.
In addition, there are 2 squares with dimensions 3 inches by 3 inches for the top and bottom faces, giving us a total area of 2 * (3 * 3) = 18 square inches.
Adding the areas of the rectangles and squares together, we get 72 + 18 = 90 square inches.
Since none of the given choices match the calculated surface area of 90 square inches, there may have been an error in the options provided. Based on the calculations, the correct surface area is 90 square inches.