Xavior took a total of 124 quarters and dimes to trade in for cash at the bank. He got exactly $25 back. How many quarters did he have?
A. 40
B. 62
C. 84
D. 100
Let q be the number of quarters and d be the number of dimes.
q + d = 124
0.25q + 0.10d = 25
From the first equation, we can solve for d:
d = 124 - q
Substitute d = 124 - q into the second equation:
0.25q + 0.10(124 - q) = 25
0.25q + 12.4 - 0.10q = 25
0.15q = 12.6
q = 84
Therefore, Xavior had 84 quarters.
C. 84