A water tank is in the shape of a right circular cylinder. The diameter is 8 feet, and the height is 21.5 feet. Find the surface area of the water tank. Use 3.14 for π.(1 point)
To find the surface area of the water tank, we need to calculate the lateral surface area and the two circular bases.
The lateral surface area of a cylinder is given by the formula:
Lateral Surface Area = 2πrh
where r is the radius of the cylinder and h is the height.
Given that the diameter is 8 feet, the radius (r) is half of the diameter:
r = 8 / 2 = 4 feet
Using h = 21.5 feet and r = 4 feet, we have:
Lateral Surface Area = 2 * 3.14 * 4 * 21.5 = 540.56 square feet
The total surface area of the water tank is the sum of the lateral surface area and the area of the two circular bases.
The area of each circular base is given by:
Circular Base Area = πr^2
Therefore, the total surface area is:
Total Surface Area = Lateral Surface Area + 2 * Circular Base Area
Total Surface Area = 540.56 + 2 * 3.14 * 4^2
Total Surface Area = 540.56 + 2 * 3.14 * 16
Total Surface Area = 540.56 + 100.48
Total Surface Area = 641.04 square feet
Therefore, the surface area of the water tank is 641.04 square feet.