A line passes through (3, –2) and (6, 2). Write an equation for the line in point-slope form.%0D%0ARewrite the equation in standard form using integers.%0D%0A%0D%0A%0D%0Ay + 2 = (x + 3); –4x + 3y = –18%0D%0A%0D%0A%0D%0Ay – 3 = (x + 2); –4x + 3y = 17%0D%0A%0D%0A%0D%0Ay – 2 = (x – 3); –4x + 3y = 18%0D%0A%0D%0A%0D%0Ay + 2 = (x – 3); –4x + 3y = –18
The correct equation in point-slope form is:
y + 2 = (x - 3)
To rewrite this equation in standard form, we can distribute on the right side:
y + 2 = x - 3
y = x - 3 - 2
y = x - 5
Therefore, the standard form of the equation is:
- x + 3y = 5