Solve the system of equations.
–x+6y=13
4x–10y=–10
To solve this system of equations, we can use the substitution method or the elimination method.
Let's use the elimination method:
1. Multiply the first equation by 4 to eliminate x:
-4x + 24y = 52
2. Write out the second equation:
4x - 10y = -10
3. Add the two equations:
-4x + 24y + 4x - 10y = 52 - 10
14y = 42
4. Divide by 14 on both sides to solve for y:
y = 3
5. Substitute y = 3 into the first equation to find x:
-x + 6(3) = 13
-x + 18 = 13
-x = -5
x = 5
Therefore, the solution to the system of equations is x = 5 and y = 3.