Solving with Elimination Practice
Complete this assessment to review what you've learned. It will not count toward your grade.
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Question
Solve the system of equations.
6x–5y=27
3x+5y=36(1 point)
To solve the system of equations using elimination, we can add the two equations together to eliminate the variable y:
6x - 5y + 3x + 5y = 27 + 36
9x = 63
x = 63 / 9
x = 7
Now that we have found the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation:
6x - 5y = 27
6(7) - 5y = 27
42 - 5y = 27
-5y = -15
y = -15 / -5
y = 3
Therefore, the solution to the system of equations is x = 7 and y = 3.