find the perimeter of a triangle who those side lengths are 11, 4 square root 2, and square root 48
To find the perimeter of a triangle, you simply add up the lengths of all three sides.
Given the side lengths are 11, 4√2, and √48, we need to simplify the third side length:
√48 = √(16 * 3)
√48 = 4√3
Now we have the three side lengths:
11, 4√2, 4√3
The perimeter is:
11 + 4√2 + 4√3
Thus, the perimeter of the triangle is 11 + 4√2 + 4√3.