3x - 4y = 40

5x -5y = 55

To solve this system of linear equations, we can use the method of substitution or elimination. Let's use the substitution method:

Given equations:
1) 3x - 4y = 40
2) 5x - 5y = 55

From equation 1:
3x - 4y = 40
=> 3x = 4y + 40
=> x = (4y + 40) / 3

Substitute x in equation 2:
5((4y + 40) / 3) - 5y = 55
(20y + 200) / 3 - 5y = 55
20y + 200 - 15y = 165
5y + 200 = 165
5y = -35
y = -7

Substitute y back into equation 1 to find x:
3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4

Therefore, the solution to the system of equations is x = 4 and y = -7.