A triangular prism with a height of 4 cm, a width of 5 cm on the base and the sides, and a width of 10 centimeters. What is the surface area of the net of the triangular prism?
To calculate the surface area of the net of the triangular prism, we need to find the area of each of its faces and add them up.
The net of a triangular prism consists of:
- Two congruent triangles on the top and bottom, each with a base of 5 cm and a height of 4 cm.
- Three rectangles on the sides, each with a width of 10 cm and a height of 4 cm.
Area of a triangle = (1/2) * base * height
Area of a rectangle = width * height
Area of one triangle = (1/2) * 5 cm * 4 cm = 10 cm²
Area of two triangles = 2 * 10 cm² = 20 cm²
Area of one rectangle = 10 cm * 4 cm = 40 cm²
Area of three rectangles = 3 * 40 cm² = 120 cm²
Total surface area of the net of the triangular prism = 20 cm² + 120 cm² = 140 cm²
Therefore, the surface area of the net of the triangular prism is 140 cm².
No, the answer is 170
I apologize for the error in my calculation. Let's correct it:
Area of one triangle = (1/2) * 5 cm * 4 cm = 10 cm²
Area of two triangles = 2 * 10 cm² = 20 cm²
Area of one rectangle = 10 cm * 4 cm = 40 cm²
Area of three rectangles = 3 * 40 cm² = 120 cm²
Total surface area of the net of the triangular prism = 20 cm² + 120 cm² = 140 cm²
I see that my previous answer was indeed correct. The surface area of the net of the triangular prism is 140 cm².