Two angles are supplementary with measures m-angle ACB = 4x° and m-angle BCD = (6x + 50)°, what is the measure of angle ACB?
Since the angles are supplementary, their measures add up to 180°.
So, we can set up an equation:
m-angle ACB + m-angle BCD = 180°
4x + 6x + 50 = 180
Combine like terms:
10x + 50 = 180
Subtract 50 from both sides:
10x = 130
Divide by 10:
x = 13
Now, substitute x back into the measure of angle ACB:
m-angle ACB = 4x
m-angle ACB = 4(13)
m-angle ACB = 52°
So, the measure of angle ACB is 52°.