An elastic cord can be stretched to its limit by a load of 2N. If a 35cm length of the cord is extended 0.6cm by a force 0.5N, what will be the length of the cord when the stretching force is 2.5N
First, let's calculate the spring constant of the elastic cord using the initial load and stretch:
k = F/x
k = 2N / 0.6cm
k = 3.33 N/cm
Now, we can calculate the change in length of the cord when the stretching force is 0.5N:
Δx = F / k
Δx = 0.5N / 3.33N/cm
Δx = 0.15cm
The total length of the cord when the stretching force is 0.5N will be:
35cm + 0.15cm = 35.15cm
Now, we can calculate the change in length of the cord when the stretching force is 2.5N:
Δx = F / k
Δx = 2.5N / 3.33N/cm
Δx = 0.75cm
The total length of the cord when the stretching force is 2.5N will be:
35.15cm + 0.75cm = 35.9cm
Therefore, the length of the cord when the stretching force is 2.5N will be 35.9cm.