Find the area of a triangle with sides that are 9 in 13 in and 18 in
To find the area of a triangle with sides of length 9 in, 13 in, and 18 in, we can use Heron's formula:
s = (9 + 13 + 18) / 2 = 20
Area = √(s(s-9)(s-13)(s-18))
Area = √(20(20-9)(20-13)(20-18))
Area = √(20*11*7*2)
Area = √(3080)
Area ≈ 55.49 square inches
Therefore, the area of the triangle is approximately 55.49 square inches.
Please choose one of the answers below
40 in squared
63 in squared
126 in squared
47 in squared