If the perimeter of a square is 8 cm, what is the length of the diagonal?
To find the length of the diagonal of a square, we can use the Pythagorean Theorem.
Let the side length of the square be represented by "s" and the length of the diagonal be represented by "d".
Given that the perimeter of the square is 8 cm, we have:
4s = 8
s = 8/4
s = 2 cm
Now, using the Pythagorean Theorem:
d^2 = s^2 + s^2
d^2 = 2^2 + 2^2
d^2 = 4 + 4
d^2 = 8
Taking the square root of both sides to solve for d:
d = √8
d ≈ 2.83 cm
Therefore, the length of the diagonal of the square is approximately 2.83 cm.