A spring of natural length 1.5cm is extended by 0.02cm by a force of 1.5N.what will the length be when the applied force is 4.0N
To calculate the spring constant, we use Hooke's Law: F = kx
Where:
F = force applied (1.5N)
k = spring constant
x = extension of the spring (0.02cm)
Rearranging for the spring constant:
k = F / x
k = 1.5N / 0.02cm
k = 75 N/cm
Now, we can use the spring constant to calculate the extension of the spring when the force applied is 4.0N:
F = kx
4.0N = 75 N/cm * x
Rearranging for x:
x = 4.0N / 75 N/cm
x = 0.0533 cm
The total length of the spring when the force applied is 4.0N would be:
Length = Natural length + extension
Length = 1.5cm + 0.0533cm
Length = 1.5533 cm
Therefore, the length of the spring when the applied force is 4.0N would be 1.5533 cm.