solve for h(2a) when h(x)=sqrt x-3 and find the domain in interval notation
To find h(2a), we substitute 2a in place of x in the given function h(x)=√x-3.
h(2a) = √(2a) - 3
Now, to find the domain of the function h(x)=√x-3 in interval notation, we need to identify the values of x for which the function is defined. The square root function is defined only for non-negative numbers or zero.
Therefore, for h(x) = √x - 3 to be defined, x must satisfy x - 3 ≥ 0, or x ≥ 3.
So the domain of h(x) in interval notation is [3, ∞).