While travelling in her car Mr. Jones sees obstruction in the road It takes him 0.8 seconds to react and put his foot on the break his cars travelling at 25 m/s if when the brakes are applied the car deaccelerates How to uniform rate of 9.3 m/s squared what is the total displacement of the car
To find the total displacement of the car, we need to first calculate the stopping distance of the car.
First, we find the time it takes for the car to stop:
Using the equation of motion: v = u + at, where:
v = final velocity (0 m/s as the car comes to a stop)
u = initial velocity (25 m/s)
a = acceleration (-9.3 m/s^2)
t = time
0 = 25 + (-9.3)t
t = 25 / 9.3
t = 2.69 seconds
Next, we find the stopping distance (total displacement) of the car:
Using the equation of motion: s = ut + (1/2)at^2
s = 25(2.69) + 0.5(-9.3)(2.69)^2
s = 67.25 - 34.71
s = 32.54 meters
Therefore, the total displacement of the car is 32.54 meters.