While driving her car mr. Jones sees An obstruction in the road it takes 0.8 seconds to yak and put her foot on the break her car is travelling at 25 m/s. When the brakes are applied the car deaccelerates Add a uniform motion of 9.3 m/s squared what is the total displacement of the car
To solve this problem, we first need to find the time it takes for the car to come to a complete stop after the brakes are applied.
Using the formula for acceleration:
Final velocity = Initial velocity + (acceleration x time)
0 = 25 - 9.3t
9.3t = 25
t = 25 / 9.3
t ≈ 2.688 seconds
Now, we can find the total distance traveled by the car using the formula:
Displacement = Initial velocity x time + 0.5 x acceleration x time^2
Displacement = 25 x 2.688 + 0.5 x 9.3 x (2.688)^2
Displacement = 67.2 + 0.5 x 9.3 x 7.220544
Displacement = 67.2 + 0.5 x 9.3 x 7.220544
Displacement ≈ 67.2 + 31.856952
Displacement ≈ 99.056952 meters
Therefore, the total displacement of the car is approximately 99.06 meters.