A ball is travelling at 50 m/s begins to roll up an inclined plane before coming to the Ball comes to a stop 80m up the incline what was the velocity of the ball 2.5s after starting up the incline
To solve this problem, we can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity (unknown)
u = initial velocity = 50 m/s
a = acceleration due to gravity = 9.8 m/s^2 (assuming the incline is at an angle such that gravity acts as acceleration)
s = distance moved up the incline = 80 m
First, let's find the time it took for the ball to reach a stop using the equation:
v = u + at
Since the ball comes to a stop:
0 = 50 + (-9.8)t
t = 50 / 9.8
t ≈ 5.10s
Now, we can find the final velocity 2.5s after starting up the incline by using the equation of motion:
v^2 = 50^2 + 2(-9.8)(80)
v^2 = 2500 - 1568
v^2 = 932
v ≈ √932
v ≈ 30.5 m/s
Therefore, the final velocity of the ball 2.5s after starting up the incline is approximately 30.5 m/s.