Mr. Maher is standing 50 m from A large bell with his throwing arm he throws the rock at the bell and he hears the sound 4.5 s later. If the speed of sound is 330 m/s what was the speed of the rock in the air
Let's break down the problem step by step:
1. The time taken for the sound of the bell to reach Mr. Maher after he throws the rock is 4.5 seconds. This means that the time taken for the rock to reach the bell is also 4.5 seconds.
2. The total distance the sound waves traveled is the sum of the distance from Mr. Maher to the bell and the distance from the bell back to Mr. Maher. This is a round trip distance, so the total distance sound waves traveled is 100 meters.
3. Given that the speed of sound is 330 m/s, the time taken for the sound to travel the total distance (100 meters) is:
Time = Distance / Speed
Time = 100 m / 330 m/s
Time = 0.303 seconds
4. Since the total time taken for the sound to reach Mr. Maher after throwing the rock is 4.5 seconds, and the time for the sound to travel the distance is 0.303 seconds, the time taken for the rock to reach the bell is:
Total time - Time for sound waves = 4.5 s - 0.303 s = 4.197 seconds
5. The distance the rock traveled is 50 meters. Using the formula:
Distance = Speed x Time (since the speed of sound is constant at 330 m/s)
50 m = Speed x 4.197 s
Speed = 50 m / 4.197 s
Speed = 11.91 m/s
So, the speed of the rock in the air was approximately 11.91 m/s.