John has to make all 3 free throws to win the game. Assume each free throw is an independent event and
that the pressure of the situation has no impact on him. If John is a 55% free throw shooter what is the
percent chance that John makes all three free throws? Do not round your answer.
Given that each free throw is an independent event, the probability of making all three free throws is calculated by multiplying the probabilities of making each individual free throw.
Let's denote the probability of making a free throw as p = 0.55. The probability of missing a free throw is 1 - p = 0.45.
Therefore, the probability of making all three free throws is:
0.55 * 0.55 * 0.55 = 0.166375
So, the percentage chance that John makes all three free throws is 16.6375%.