Given g(x)=3x+4 and h(x)=sqrt x-3 find and simplify. State domain when necessary.
Solve 2g(3)+h(12) where it equals to 29
To find 2g(3):
g(3) = 3(3) + 4 = 9 + 4 = 13
2g(3) = 2*13 = 26
To find h(12):
h(12) = sqrt(12) - 3 = 2 * sqrt(3) - 3
Now, to solve 2g(3) + h(12) = 29:
2g(3) + h(12) = 26 + 2*sqrt(3) - 3 = 29 + 2*sqrt(3)
The value of 2g(3)+h(12) equals 29 if it is written as 29 + 2*sqrt(3).
The domain for h(x) is x ≥ 0 since square root cannot be negative.