what is the inverse of f if f(x) = ^3 sq root of x - 5.
f^-1(x) = x^3 + 5
f^-1(x) = 1/^3 sq root x - 5
f^-1(x) = x^3 + 125
f^-1(x) = 5 - ^3 sq root x
The correct inverse function of f(x) = ^3 sq root of x - 5 is:
f^-1(x) = (x + 5)^3
f^-1(x) = x^3 + 5
f^-1(x) = 1/^3 sq root x - 5
f^-1(x) = x^3 + 125
f^-1(x) = 5 - ^3 sq root x
f^-1(x) = (x + 5)^3