Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P’?
2,0
2,12
6,0
10,4
The correct answer is 6,0.
To find the new coordinates of P', you simply need to subtract 6 from the x-coordinate and add 2 to the y-coordinate of P.
P(8,2) -> P'(8-2,2-6) -> P'(6,0)