The pair of figures to the right are similar. The area of one figure is given. Find the area of the other figure to the nearest whole number.
Area of smaller parallelogramequals8 ft squared
4 ft
16 ft
Two similar figures: the first has side length 4 feet and the other of side length 16 feet.
Since the two figures are similar, their sides are in proportion.
If the side length of the smaller parallelogram is 4 feet and its area is 8 ft squared, then the side length of the larger parallelogram is 16 feet.
Therefore, the area of the larger parallelogram would be:
(16 ft / 4 ft)^2 x 8 ft^2 = 64 ft^2
So, the area of the larger parallelogram is 64 ft squared.