For the triangle shown <B= 34 degrees and CD= 80
Solve for DB to the nearest tenth
Since the sum of the angles in a triangle is 180 degrees, we can find angle <D as follows:
<D = 180 - 90 - 34
<D = 56 degrees
Now, we can use the Law of Sines to solve for the length of side DB:
sin(<B) / BD = sin(<D) / CD
sin(34) / BD = sin(56) / 80
BD = sin(34) * 80 / sin(56)
BD ≈ 64.6
Therefore, the length of side DB is approximately 64.6 units.
who said it was a right triangle?
I apologize for assuming that it was a right triangle.
Given that <B = 34 degrees in the triangle, we can use the Law of Sines to solve for the length of side DB:
sin(B) / BD = sin(D) / CD
sin(34) / DB = sin(180 - 34 - D) / 80
sin(34) / DB = sin(D - 34) / 80
sin(34) / DB = sin(D)cos(34) - cos(D)sin(34) / 80
We can't directly solve for DB because the values of sin(D) and cos(D) are unknown. If you can provide additional information or context, I would be glad to assist further.