Calculate the volume of Co2 that would be produced from 0.5 mole of Fe2O3 according to the following equation
The balanced chemical equation for the reaction of Fe2O3 with CO is:
Fe2O3(s) + 3CO(g) -> 2Fe(s) + 3CO2(g)
According to the equation, 3 moles of CO are required to produce 3 moles of CO2. Therefore, 1 mole of CO produces 1 mole of CO2.
Given that 0.5 moles of Fe2O3 react with CO, we can calculate the volume of CO2 produced using the ideal gas law:
n = PV / RT
Where:
n = moles of CO2
P = pressure (assume 1 atm)
V = volume of gas
R = ideal gas constant (0.0821 L*atm/mol*K)
T = temperature (assume room temperature, 298 K)
Convert moles of Fe2O3 to moles of CO2:
0.5 moles of Fe2O3 * (3 moles of CO2 / 1 mole of Fe2O3) = 1.5 moles of CO2
Now, substitute the values into the equation:
1.5 moles = (1 atm) * V / (0.0821 L*atm/mol*K * 298 K)
V = (1.5 moles * 0.0821 L*atm/mol*K * 298 K) / 1 atm
V ≈ 36.9 L
Therefore, 0.5 moles of Fe2O3 would produce 36.9 L of CO2 gas.