Suppose f(x)=9x-9 and g(x)= sqrt (x^2-4x+9)
(f of g)(x)=
(f of g)(-2)=
To find (f of g)(x), we need to first find g(x) and then plug it into f(x).
First, we need to find g(x):
g(x) = sqrt(x^2 - 4x + 9)
Now, we need to find (f of g)(x):
(f of g)(x) = f(g(x)) = f(sqrt(x^2 - 4x + 9))
Now, plug g(x) = sqrt(x^2 - 4x + 9) into f(x) = 9x - 9:
(f of g)(x) = 9(sqrt(x^2 - 4x + 9)) - 9 = 9(sqrt(x^2 - 4x + 9)) - 9
So, (f of g)(x) = 9(sqrt(x^2 - 4x + 9)) - 9
Now, to find (f of g)(-2), we plug in x = -2:
(f of g)(-2) = 9(sqrt((-2)^2 - 4(-2) + 9)) - 9
(f of g)(-2) = 9(sqrt(4 + 8 + 9)) - 9
(f of g)(-2) = 9(sqrt(21)) - 9
Therefore, (f of g)(-2) = 9(sqrt(21)) - 9.