a car with mass of 1250 kg travels at 2.24 m/s and bumps into a car with a mass of 1300 kg after the collision the two cars stick together and move forward. how fast they both move forward ? round to two decimal places
To solve this problem, we can use the principle of conservation of momentum.
First, we need to calculate the initial momentum of the first car before the collision:
Initial momentum = mass x velocity
Initial momentum = 1250 kg x 2.24 m/s
Initial momentum = 2800 kg*m/s
Next, we need to calculate the initial momentum of the second car before the collision:
Initial momentum = mass x velocity
Initial momentum = 1300 kg x 0 m/s (since the second car is stationary)
Initial momentum = 0 kg*m/s
Now, after the collision, the two cars stick together and move forward as one object. Let's call their final velocity Vf. The total mass of the two cars combined is 1250 kg + 1300 kg = 2550 kg.
Using the principle of conservation of momentum, we can set up the following equation:
Initial momentum of first car + initial momentum of second car = final momentum of combined cars
2800 kg*m/s + 0 kg*m/s = 2550 kg x Vf
2800 kg*m/s = 2550 kg x Vf
Vf = 2800 kg*m/s / 2550 kg
Vf = 1.098 m/s
Therefore, after the collision, the two cars move forward at a speed of 1.10 m/s.