Questions
a ball rolls 3.2m up a constant slope before it comes to a stop if the initial velocity of the ball was 2.2m/s what is the acceleration of the ball as it rolls
To find the acceleration of the ball as it rolls up the slope, we first need to determine the final velocity when the ball comes to a stop at the end of the 3.2m distance.
Using the kinematic equation:
v_f^2 = v_i^2 + 2ad
Where:
v_f = final velocity (0 m/s at the top of the slope)
v_i = initial velocity (2.2 m/s)
a = acceleration (unknown)
d = distance (3.2m)
Plugging in the values:
0 = (2.2)^2 + 2a(3.2)
0 = 4.84 + 6.4a
-4.84 = 6.4a
a = -0.75 m/s^2
Therefore, the acceleration of the ball as it rolls up the slope is -0.75 m/s^2. The negative sign indicates that the acceleration is in the opposite direction of the motion.