You must find the xx-intercept(s) of f, of, xf(x) and write the answer(s) in the form (x,y)
f(x)=2x^2+4x−30
To find the x-intercepts of a function, we need to set y = 0 and solve for x.
1. f(x) = 2x^2 + 4x - 30
Set f(x) = 0:
0 = 2x^2 + 4x - 30
Simplify:
0 = 2x^2 + 4x - 30
Divide by 2 to simplify the equation:
0 = x^2 + 2x - 15
Factor the quadratic equation:
0 = (x - 3)(x + 5)
x = 3 or x = -5
Therefore, the x-intercepts of f(x) = 2x^2 + 4x - 30 are:
(3,0) and (-5,0)