The sailboat in Question #1 returns to port in a straight line from its current position. The captain would like to know the total distance traveled (refer to distances in question #1).
1. What was the total distance traveled?
2. What was the final displacement?
1. 5.3+2.5+5.86= 13.66km
2.would i double 13.66?
Not knowing the path, it is impossible for me to add anything.
oh wow im sorry! :)
A sailboat sails west from port for 5.3 km and experiences a shift in the wind direction. The wind blows the sailboat 2.5 km south. What is its displacement from its original position?
a^2+b^2=c^2
5.3^2+2.5^2=5.86^2SW
displacement= sqrt(5.3^2+2.5^2)
Now, the angle: Tan Theta= 2.5/5.3
so Theta = arctan(2.5/5.3) S of W
what is theta and arctan?!
To find the total distance traveled by the sailboat, you can add up the individual distances traveled in Question #1. In this case, the total distance traveled is 5.3 km + 2.5 km + 5.86 km, which equals 13.66 km.
For the final displacement, it refers to the straight-line distance from the starting point to the ending point. Since the sailboat returns to the starting point, the final displacement is zero. Therefore, you do not need to double the total distance traveled; the final displacement is simply zero.