Transform the linear equation −2y=14−6x to slope-intercept form..
To transform the linear equation −2y = 14 - 6x to slope-intercept form (y = mx + b):
First, divide both sides of the equation by -2 to get y by itself:
y = -7 + 3x
Therefore, the equation in slope-intercept form is y = 3x - 7.
Write 0.4x+0.2y=0.6 in slope-intercept form.
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form (y = mx + b), we need to solve for y:
0.2y = -0.4x + 0.6
y = (-0.4x + 0.6) / 0.2
y = -2x + 3
Therefore, the equation in slope-intercept form is y = -2x + 3.
Write the linear equation 3y=6x−18 in slope-intercept form.(1 point)
To write the equation 3y = 6x - 18 in slope-intercept form (y = mx + b), we need to solve for y:
Divide the entire equation by 3:
y = 2x - 6
Therefore, the equation in slope-intercept form is y = 2x - 6.
What is the slope and the y-intercept of the equation 9+272x=−32y. Write the y-intercept as an ordered pair.(1 point)
The slope is
. The y-intercept is (
).
To find the slope and y-intercept of the equation 9 + 27x = -32y, we need to rewrite it in the slope-intercept form:
-32y = 9 + 27x
y = -(27x/32) - 9/32
The slope of the equation is the coefficient of x, which is -27/32.
To find the y-intercept, substitute x = 0 into the equation:
y = -0 - 9/32
y = -9/32
Therefore, the slope is -27/32 and the y-intercept is the point (0, -9/32).
wrong
I apologize for the mistake in my previous response. Let's correct it:
Given the equation 9 + 27x = -32y.
Rewriting this equation in slope-intercept form (y = mx + b):
-32y = 9 + 27x
y = -(27/32)x - 9/32
The slope of the equation is -27/32.
To find the y-intercept as an ordered pair, we set x = 0 in the equation:
y = -(27/32)(0) - 9/32
y = -9/32
Therefore, the slope is -27/32 and the y-intercept as an ordered pair is (0, -9/32).